Statics 13th Edition Solutions Manual

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The members of a truss are pin connected at joint O. Determine the magnitudes of F1 and F2 for equilibrium. Y 5 kN F2 70⬚ 30⬚ x SOLUTION + ©F = 0;: x O F2 sin 70° + F1 cos 60° - 5 cos 30° - 4 (7) = 0 5 5 3 4 0.9397F2 + 0.5F1 = 9.930 7 kN + c ©Fy = 0; u 3 F2 cos 70° + 5 sin 30° - F1 sin 60° - (7) = 0 5 F1 Solving: T an his th d wo sa eir is p rk w le co ro is ill o u vi pr de f a rse de ot st ny s d s ec ro p an o te y ar d le d th t o a ly by e s in f th se for Un te is ss th ite gr w in e ity o g us d S of rk ( stu e o tat th inc de f i es e lu nt ns co w d le tr p or in a uc y k g rn to rig an on in rs h d th g. In t la is e D t w no W iss ea s t p or em ch in er ld m W ina g itt id tio ed e n. We or b) 0.3420F2 - 0.8660F1 = 1.7 F2 = 9.60 kN Ans. F1 = 1.83 kN Ans. © 2013 Pearson Education, Inc., Upper Saddle River, NJ.

Engineering Mechanics Statics 13th Hibbeler
Engineering Statics 13th Edition Pdf

All rights reserved. This publication is protected by Copyright and written permission should be obtained from the publisher prior to any prohibited reproduction, storage in a retrieval system, or transmission in any form or by any means, electronic, mechanical, photocopying, recording, or likewise. For information regarding permission(s), write to: Rights and Permissions Department, Pearson Education, Inc., Upper Saddle River, NJ 07458. The members of a truss are pin connected at joint O. Determine the magnitude of F1 and its angle u for equilibrium.

Set F2 = 6 kN. Y 5 kN F2 70⬚ 30⬚ x SOLUTION + ©F = 0;: x O 6 sin 70° + F1 cos u - 5 cos 30° - 4 (7) = 0 5 5 F1 cos u = 4.2920 + c ©Fy = 0; 6 cos 70° + 5 sin 30° - F1 sin u - u 3 4 3 (7) = 0 5 7 kN F1 F1 sin u = 0.3521 Solving: Ans. F1 = 4.31 kN Ans. T an his th d wo sa eir is p rk w le co ro is ill o u vi pr de f a rse de ot st ny s d s ec ro p an o te y ar d le d th t o a ly by e s in f th se for Un te is ss th ite gr w in e ity o g us d S of rk ( stu e o tat th inc de f i es e lu nt ns co w d le tr p or in a uc y k g rn to rig an on in rs h d th g.

In t la is e D t w no W iss ea s t p or em ch in er ld m W ina g itt id tio ed e n. We or b) u = 4.69° © 2013 Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved. This publication is protected by Copyright and written permission should be obtained from the publisher prior to any prohibited reproduction, storage in a retrieval system, or transmission in any form or by any means, electronic, mechanical, photocopying, recording, or likewise. For information regarding permission(s), write to: Rights and Permissions Department, Pearson Education, Inc., Upper Saddle River, NJ 07458. Cords AB and AC can each sustain a maximum tension of 800 lb. If the drum has a weight of 900 lb, determine the smallest angle u at which they can be attached to the drum.

B A u u C SOLUTION + c ©Fy = 0; 900 - 2(800) sin u = 0 Ans. T an his th d wo sa eir is p rk w le co ro is ill o u vi pr de f a rse de ot st ny s d s ec ro p an o te y ar d le d th t o a ly by e s in f th se for Un te is ss th ite gr w in e ity o g us d S of rk ( stu e o tat th inc de f i es e lu nt ns co w d le tr p or in a uc y k g rn to rig an on in rs h d th g. In t la is e D t w no W iss ea s t p or em ch in er ld m W ina g itt id tio ed e n. We or b) u = 34.2° © 2013 Pearson Education, Inc., Upper Saddle River, NJ.

All rights reserved. This publication is protected by Copyright and written permission should be obtained from the publisher prior to any prohibited reproduction, storage in a retrieval system, or transmission in any form or by any means, electronic, mechanical, photocopying, recording, or likewise. For information regarding permission(s), write to: Rights and Permissions Department, Pearson Education, Inc., Upper Saddle River, NJ 07458. The members of a truss are connected to the gusset plate. If the forces are concurrent at point O, determine the magnitudes of F and T for equilibrium. Take u = 30°. A O 8 kN u 45 D B SOLUTION + ©F = 0;: x T T = 13.32 = 13.3 kN + c ©Fy = 0; C -T cos 30° + 8 + 5 sin 45° = 0 Ans.

5 kN F F - 13.32 sin 30° - 5 cos 45° = 0 Ans. T an his th d wo sa eir is p rk w le co ro is ill o u vi pr de f a rse de ot st ny s d s ec ro p an o te y ar d le d th t o a ly by e s in f th se for Un te is ss th ite gr w in e ity o g us d S of rk ( stu e o tat th inc de f i es e lu nt ns co w d le tr p or in a uc y k g rn to rig an on in rs h d th g. In t la is e D t w no W iss ea s t p or em ch in er ld m W ina g itt id tio ed e n. We or b) F = 10.2 kN © 2013 Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved. This publication is protected by Copyright and written permission should be obtained from the publisher prior to any prohibited reproduction, storage in a retrieval system, or transmission in any form or by any means, electronic, mechanical, photocopying, recording, or likewise. For information regarding permission(s), write to: Rights and Permissions Department, Pearson Education, Inc., Upper Saddle River, NJ 07458.

The device shown is used to straighten the frames of wrecked autos. Determine the tension of each segment of the chain, i.e., AB and BC, if the force which the hydraulic cylinder DB exerts on point B is 3.50 kN, as shown. B A 3.50 kN D 450 mm C 400 mm 250 mm SOLUTION Equations of Equilibrium: A direct solution for FBC can be obtained by summing forces along the y axis. + c ©Fy = 0; 3.5 sin 48.37° - FBC sin 60.95° = 0 FBC = 2.993 kN = 2.99 kN Ans. Using the result FBC = 2.993 kN and summing forces along x axis, we have 3.5 cos 48.37° + 2.993 cos 60.95° - FAB = 0 T an his th d wo sa eir is p rk w le co ro is ill o u vi pr de f a rse de ot st ny s d s ec ro p an o te y ar d le d th t o a ly by e s in f th se for Un te is ss th ite gr w in e ity o g us d S of rk ( stu e o tat th inc de f i es e lu nt ns co w d le tr p or in a uc y k g rn to rig an on in rs h d th g.

In t la is e D t w no W iss ea s t p or em ch in er ld m W ina g itt id tio ed e n. We or b) + ©F = 0;: x FAB = 3.78 kN Ans. © 2013 Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved. This publication is protected by Copyright and written permission should be obtained from the publisher prior to any prohibited reproduction, storage in a retrieval system, or transmission in any form or by any means, electronic, mechanical, photocopying, recording, or likewise.

For information regarding permission(s), write to: Rights and Permissions Department, Pearson Education, Inc., Upper Saddle River, NJ 07458. Two electrically charged pith balls, each having a mass of 0.2 g, are suspended from light threads of equal length. Determine the resultant horizontal force of repulsion, F, acting on each ball if the measured distance between them is r = 200 mm.

⫹ ⫹ ⫹ A SOLUTION + ©F = 0;: x F - Ta + c ©Fy = 0; TB 50 mm 150 mm ⫹ ⫹ ⫹ ⴚF 150 mm F ⫹ ⫹ ⫹ r ⫽ 200 mm ⫹ ⫹ ⫹ ⫹ ⫹ B 75 b = 0 150 21502 - 752 R - 0.2(9.81)(10 - 3) = 0 150 T = 2.266(10 - 3) N Ans. T an his th d wo sa eir is p rk w le co ro is ill o u vi pr de f a rse de ot st ny s d s ec ro p an o te y ar d le d th t o a ly by e s in f th se for Un te is ss th ite gr w in e ity o g us d S of rk ( stu e o tat th inc de f i es e lu nt ns co w d le tr p or in a uc y k g rn to rig an on in rs h d th g. In t la is e D t w no W iss ea s t p or em ch in er ld m W ina g itt id tio ed e n. We or b) F = 1.13 mN © 2013 Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved.

This publication is protected by Copyright and written permission should be obtained from the publisher prior to any prohibited reproduction, storage in a retrieval system, or transmission in any form or by any means, electronic, mechanical, photocopying, recording, or likewise. For information regarding permission(s), write to: Rights and Permissions Department, Pearson Education, Inc., Upper Saddle River, NJ 07458. Determine the tension developed in wires CA and CB required for equilibrium of the 10-kg cylinder. Take u = 40°. B A u 30° C SOLUTION Equations of Equilibrium: Applying the equations of equilibrium along the x and y axes to the free-body diagram shown in Fig. A, + ©F = 0;: x FCB cos 40° - FCA cos 30° = 0 (1) + c ©Fy = 0; FCB sin 40° + FCA sin 30° - 10(9.81) = 0 (2) Solving Eqs. (1) and (2), yields FCB = 90.4 N Ans.

All rights reserved. This publication is protected by Copyright and written permission should be obtained from the publisher prior to any prohibited reproduction, storage in a retrieval system, or transmission in any form or by any means, electronic, mechanical, photocopying, recording, or likewise. For information regarding permission(s), write to: Rights and Permissions Department, Pearson Education, Inc., Upper Saddle River, NJ 07458. If cable CB is subjected to a tension that is twice that of cable CA, determine the angle u for equilibrium of the 10-kg cylinder.

Also, what are the tensions in wires CA and CB? B A u 30° C SOLUTION Equations of Equilibrium: Applying the equations of equilibrium along the x and y axes, + ©F = 0;: x FCB cos u - FCA cos 30° = 0 (1) + c ©Fy = 0; FCB sin u + FCA sin 30° - 10(9.81) = 0 (2) However, it is required that FCB = 2FCA T an his th d wo sa eir is p rk w le co ro is ill o u vi pr de f a rse de ot st ny s d s ec ro p an o te y ar d le d th t o a ly by e s in f th se for Un te is ss th ite gr w in e ity o g us d S of rk ( stu e o tat th inc de f i es e lu nt ns co w d le tr p or in a uc y k g rn to rig an on in rs h d th g. In t la is e D t w no W iss ea s t p or em ch in er ld m W ina g itt id tio ed e n. We or b) (3) Solving Eqs. (1), (2), and (3), yields u = 64.3° FCB = 85.2 N FCA = 42.6 N Ans.

© 2013 Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved. This publication is protected by Copyright and written permission should be obtained from the publisher prior to any prohibited reproduction, storage in a retrieval system, or transmission in any form or by any means, electronic, mechanical, photocopying, recording, or likewise. For information regarding permission(s), write to: Rights and Permissions Department, Pearson Education, Inc., Upper Saddle River, NJ 07458. Blocks D and F weigh 5 lb each and block E weighs 8 lb.

Determine the sag s for equilibrium. Neglect the size of the pulleys. 4 ft 4 ft C B s A SOLUTION + c ©Fy = 0; 2(5) sin u - 8 = 0 D E u = sin - 1(0.8) = 53.13° tan u = s 4 Ans. T an his th d wo sa eir is p rk w le co ro is ill o u vi pr de f a rse de ot st ny s d s ec ro p an o te y ar d le d th t o a ly by e s in f th se for Un te is ss th ite gr w in e ity o g us d S of rk ( stu e o tat th inc de f i es e lu nt ns co w d le tr p or in a uc y k g rn to rig an on in rs h d th g. In t la is e D t w no W iss ea s t p or em ch in er ld m W ina g itt id tio ed e n. We or b) s = 4 tan 53.13° = 5.33 ft © 2013 Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved.

If blocks D and F weigh 5 lb each, determine the weight of block E if the sag s = 3 ft. Neglect the size of the pulleys. 4 ft 4 ft C B s A SOLUTION + c ©Fy = 0; D 3 2(5)a b - W = 0 5 F Ans. T an his th d wo sa eir is p rk w le co ro is ill o u vi pr de f a rse de ot st ny s d s ec ro p an o te y ar d le d th t o a ly by e s in f th se for Un te is ss th ite gr w in e ity o g us d S of rk ( stu e o tat th inc de f i es e lu nt ns co w d le tr p or in a uc y k g rn to rig an on in rs h d th g. In t la is e D t w no W iss ea s t p or em ch in er ld m W ina g itt id tio ed e n.

We or b) W = 6 lb E © 2013 Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved. This publication is protected by Copyright and written permission should be obtained from the publisher prior to any prohibited reproduction, storage in a retrieval system, or transmission in any form or by any means, electronic, mechanical, photocopying, recording, or likewise. For information regarding permission(s), write to: Rights and Permissions Department, Pearson Education, Inc., Upper Saddle River, NJ 07458. The 10-lb lamp fixture is suspended from two springs, each having an unstretched length of 4 ft and stiffness of k = 5 lbft. Determine the angle u for equilibrium. 4 ft u k ⫽ 5 lb/ft 4 ft u k ⫽ 5 lb/ft SOLUTION + ©F = 0;: x + c ©Fy = 0; T cos u - T cos u = 0 2T sin u - 10 = 0 T sin u = 5 lb F = ks; T = 5a 4 - 4b cos u 20 a 1 - 1b cos u T an his th d wo sa eir is p rk w le co ro is ill o u vi pr de f a rse de ot st ny s d s ec ro p an o te y ar d le d th t o a ly by e s in f th se for Un te is ss th ite gr w in e ity o g us d S of rk ( stu e o tat th inc de f i es e lu nt ns co w d le tr p or in a uc y k g rn to rig an on in rs h d th g.

In t la is e D t w no W iss ea s t p or em ch in er ld m W ina g itt id tio ed e n. We or b) T = 20 a sin u - sin ub = 5 cos u tan u - sin u = 0.25 Solving by trial and error, u = 43.0° Ans. © 2013 Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved. This publication is protected by Copyright and written permission should be obtained from the publisher prior to any prohibited reproduction, storage in a retrieval system, or transmission in any form or by any means, electronic, mechanical, photocopying, recording, or likewise.

For information regarding permission(s), write to: Rights and Permissions Department, Pearson Education, Inc., Upper Saddle River, NJ 07458. Determine the mass of each of the two cylinders if they cause a sag of s = 0.5 m when suspended from the rings at A and B. Note that s = 0 when the cylinders are removed. 2m 1m 2m D C 1.5 m s k SOLUTION 100 N/m k A 100 N/m B TAC = 100 Nm (2.828 - 2.5) = 32.84 N + c ©Fy = 0; 32.84 sin 45° - m(9.81) = 0 Ans.

T an his th d wo sa eir is p rk w le co ro is ill o u vi pr de f a rse de ot st ny s d s ec ro p an o te y ar d le d th t o a ly by e s in f th se for Un te is ss th ite gr w in e ity o g us d S of rk ( stu e o tat th inc de f i es e lu nt ns co w d le tr p or in a uc y k g rn to rig an on in rs h d th g. In t la is e D t w no W iss ea s t p or em ch in er ld m W ina g itt id tio ed e n. We or b) m = 2.37 kg © 2013 Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved. This publication is protected by Copyright and written permission should be obtained from the publisher prior to any prohibited reproduction, storage in a retrieval system, or transmission in any form or by any means, electronic, mechanical, photocopying, recording, or likewise. For information regarding permission(s), write to: Rights and Permissions Department, Pearson Education, Inc., Upper Saddle River, NJ 07458. The unstretched length of spring AB is 3 m.

Engineering Mechanics Statics 13th Hibbeler

If the block is held in the equilibrium position shown, determine the mass of the block at D. 3m 4m C 3m B 20 N/m kAC kAB 30 N/m SOLUTION A F = kx = 30(5 - 3) = 60 N + ©F = 0;: x 4 Tcos 45° - 60 a b = 0 5 T = 67.88 N D + c ©Fy = 0; 3 -W + 67.88 sin 45° + 60 a b = 0 5 W = 84 N 84 = 8.56 kg 9.81 Ans. T an his th d wo sa eir is p rk w le co ro is ill o u vi pr de f a rse de ot st ny s d s ec ro p an o te y ar d le d th t o a ly by e s in f th se for Un te is ss th ite gr w in e ity o g us d S of rk ( stu e o tat th inc de f i es e lu nt ns co w d le tr p or in a uc y k g rn to rig an on in rs h d th g. In t la is e D t w no W iss ea s t p or em ch in er ld m W ina g itt id tio ed e n. We or b) m = © 2013 Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved.

Engineering Mechanics Statics 13th Hibbeler

Engineering Statics 13th Edition Pdf